数学题=y(y+3)-4(y+3)2=(y+3)(y-4y-12)

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/29 06:02:57
数学题=y(y+3)-4(y+3)2=(y+3)(y-4y-12)

数学题=y(y+3)-4(y+3)2=(y+3)(y-4y-12)
数学题=y(y+3)-4(y+3)2=(y+3)(y-4y-12)

数学题=y(y+3)-4(y+3)2=(y+3)(y-4y-12)
(y+3)^2/8-y=(y+3)/4-(y-1)/2
各项都乘以8,得
(y+3)^2-8y=2(y+3)-4(y-1)
y^2-2y+9=-2y+10
y^2=1
y1=-1 y2=1

解决方案:

比索(1)Y = -x方-4x +3


= - (X平方-4x + 4-4)3
BR>
= - (x-2)的平方+ 4 + 3


= - (x-2)的平方7

日(2)Y =第四点ˉx平方-x +1


= 4分之1(X平方-4x + 4) - 中东= 4点第1条(X-2)的平方的