sin4次方θ+cos4次方θ=1,sinθ-cosθ=

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sin4次方θ+cos4次方θ=1,sinθ-cosθ=
sin4次方θ+cos4次方θ=1,sinθ-cosθ=

sin4次方θ+cos4次方θ=1,sinθ-cosθ=
Sin4次方θ+cos4次方θ=1
Sin4次方θ+cos4次方θ+2Sin2次方θcos2次方θ-2Sin2次方θcos2次方θ=1
(Sin2次方θ+cos2次方θ)2次方-2Sin2次方θcos2次方θ=1
1-2Sin2次方θcos2次方θ=1
2Sin2次方θcos2次方θ=1
4Sin2次方θcos2次方θ=1
(2Sinθcosθ)2次方=1
2Sinθcosθ=1
(sinθ-cosθ)2次方=1-2Sinθcosθ=1-1=0
sinθ-cosθ=0

sin^4θ+cos^4θ=1

sin^4θ+cos^4θ+2sin^2θcos^2θ-2sin^2θcos^2θ=1

(sin^2θ+cos^2θ)^2-2sin^2θcos^2θ=1

1-2sin^2θcos^2θ=1

2sin^2θcos^2θ=0

(sin2θ)^2=0

2θ=kπ

θ=kπ/2

sinθ-cosθ

=sin(kπ/2)-cos(kπ/2)

=sin(kπ/2)

=(-1)^(k+1)

sin4次方θ-cos4次方θ=5/9 求cos4θ sin4次方θ+cos4次方θ=1,sinθ-cosθ= sinθ+cosθ=1/3,求sin4次方θ+cos4次方θ 求证sin4次方—cos4次方=2sina-1 cos4次方α-sin4次方α=?, 已知sin4次方-cos4次方=5/9,求cos4 Sin4次方θ+cos4次方θ=5/9,求sin2θ是? 已知cos2θ=3/9,求sin4次方θ+cos4次方θ的值证明1.sin4次方+cos4次方=1-2sin2次方acos2次方求证sin4次方α+cos4次方α=1-1/2sin2次方α (1+sin4θ-cos4θ)/(1+sin4θ+cos4θ)-(1+sin4θ+cos4θ)/(1+sin4θ-cos4θ) 求证:cos4次方a-sin4次方a=cos2a 已知2θ＝根号2/3 则sin4次方θ-cos4次方θ＝已知cos2a=1/3,则sin4次方a+cos4次方a的值为已知cos2a=1/3,则sin4次方a+cos4次方a的值为化简sin4次方X+cos4次方X 已知sinθ-cosθ=m,则sin4θ+cos4θ=用m表示,4是4次方 sin4θ+cos4θ怎样化简?4是四次方