已知数列an=1/[n(n+1)(n+2)],求Sn的极限

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已知数列an=1/[n(n+1)(n+2)],求Sn的极限

已知数列an=1/[n(n+1)(n+2)],求Sn的极限
已知数列an=1/[n(n+1)(n+2)],求Sn的极限

已知数列an=1/[n(n+1)(n+2)],求Sn的极限
An=1/2*[1/n(n+1)-1/(n+1)(n+2)]
Sn=1/2*[1/2-\1/6+1/6-1/12+.+1/n(n+1)-1/(n+1)(n+2)]
=1/2*[1/2-1/(n+1)(n+2)]