已知x+y+z=2,xy+yz+zx=-5,求x²+y²+z²的值

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已知x+y+z=2,xy+yz+zx=-5,求x²+y²+z²的值

已知x+y+z=2,xy+yz+zx=-5,求x²+y²+z²的值
已知x+y+z=2,xy+yz+zx=-5,求x²+y²+z²的值

已知x+y+z=2,xy+yz+zx=-5,求x²+y²+z²的值
(x+y+z)^2=4
x^2+y^2+z^2+2xy+2xz+2yz=4
x^2+y^2+z^2+2(-5)=4
x^2+y^2+z^2=14

(x+y+z)²=x²+y²+z²+2xy+2yz+2xz
4=(x²+y²+z²)-10
x²+y²+z²=14

(x+y+z)^2=x^2+y^2+z^2+2xy+2yz+2xz
x²+y²+z²=(x+y+z)^2-2(xy+yz+zx)=4+10=14