lim(x→0) 1-cosx/x+x
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![lim(x→0) 1-cosx/x+x](/uploads/image/z/3738758-14-8.jpg?t=lim%EF%BC%88x%E2%86%920%EF%BC%89+1-cosx%2Fx%EF%BC%8Bx)
lim(x→0) 1-cosx/x+x
lim(x→0) 1-cosx/x+x
lim(x→0) 1-cosx/x+x
lim(x→0) sinx/(2x+1)
=0
原式=lim[(1-cosx)/x]×lim[x/(x+1)]
=(1/2)×0
=0
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