(cos10°-cos50°)÷(sin10°-sin50°)

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/07 03:21:35
(cos10°-cos50°)÷(sin10°-sin50°)

(cos10°-cos50°)÷(sin10°-sin50°)
(cos10°-cos50°)÷(sin10°-sin50°)

(cos10°-cos50°)÷(sin10°-sin50°)
原式=[cos(30-20)-cos(30+20)]÷[sin(30-20)-sin(30+20)]
=(cos30cos20+sin30sin20-cos30cos20+sin30sin20)÷(sin30cos20-cos30sin20-sin30cos20-cos30sin20)
=2sin30sin20÷(-2cos30sin20)
=-sin30/cos30
=-√3/3

cos α-cos β=-2sin[(α+β)/2]·sin[(α-β)/2]
所以cos10°-cos50=2sin[30°]·sin[20°]
sin α-sin β=2cos[(α+β)/2]·sin[(α-β)/2]
所以sin10°-sin50°)=-2cos[30°]·sin[20°]
所以(cos10°-cos50°)÷(sin10°-sin50°)
=-2sin[30°]·sin[20°] /2cos[30°]·sin[20°]
=-tan30°=-√3/3