当x=9/2时,求(x^2+7x+10)/(x^2+6x+5)×(x^3+1)/(x^2+4x+4)÷(x^2-x+1)/(x+2)

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/29 12:10:35
当x=9/2时,求(x^2+7x+10)/(x^2+6x+5)×(x^3+1)/(x^2+4x+4)÷(x^2-x+1)/(x+2)

当x=9/2时,求(x^2+7x+10)/(x^2+6x+5)×(x^3+1)/(x^2+4x+4)÷(x^2-x+1)/(x+2)
当x=9/2时,求(x^2+7x+10)/(x^2+6x+5)×(x^3+1)/(x^2+4x+4)÷(x^2-x+1)/(x+2)

当x=9/2时,求(x^2+7x+10)/(x^2+6x+5)×(x^3+1)/(x^2+4x+4)÷(x^2-x+1)/(x+2)
(x^2+7x+10)/(x^2+6x+5)×(x^3+1)/(x^2+4x+4)÷(x^2-x+1)/(x+2)
=(x+2)(x+5)/(x+1)(x+5)*(x+1)(x^2-x+1)/(x+2)^2÷(x^2-x+1)/(x+2)
=(x+2)(x+5)/(x+1)(x+5) * (x+1)(x^2-x+1)/(x+2)^2 * (x+2)/(x^2-x+1)
=1

只要X不等于-2,-5,-1,那么最后值恒等于 1

原式=(x+2)(x+5)/[(x+1)(x+5)]X(x+1)(x^2-x+1)/[(x+2)^2(x^2-x+1)]/(X+2)=(x+2)^2
代入数据得到169/4
不知道你输入的原式对不对

代入不就好了