2001×(1÷8-1÷2009)+8×(1÷2001-1÷2009)-2009×(1÷8+1÷2001)+8累死人的简便计算······
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/03 05:18:50
2001×(1÷8-1÷2009)+8×(1÷2001-1÷2009)-2009×(1÷8+1÷2001)+8累死人的简便计算······
2001×(1÷8-1÷2009)+8×(1÷2001-1÷2009)-2009×(1÷8+1÷2001)+8
累死人的简便计算······
2001×(1÷8-1÷2009)+8×(1÷2001-1÷2009)-2009×(1÷8+1÷2001)+8累死人的简便计算······
2001×(1÷8-1÷2009)+8×(1÷2001-1÷2009)-2009×(1÷8+1÷2001)+8
先乘出来,再合并
=2001/8-2001/2009+8/2001-8/2009-2009/8-2009/2001+8
=2001/8-2009/8-2001/2009-8/2009+8/2001-2009/2001+8
=(2001-2009)/8-(2001+8)/2009-(2009-8)/2001+8
=(-8)/8-(2009)/2009-(2001)/2001+8
=-1-1-1+8
=5
2001*(1/8-1/2009) 8*(1/2001-1/2009)-2009*(1/8 1/2001) 8
=1/8*(2001-2009)-1/2009*(2001 8) 1/2001*(8-2009) 8
=-1-1-1 8
=5
2001×(1÷8-1÷2009)+8×(1÷2001-1÷2009)-2009×(1÷8+1÷2001)+8累死人的简便计算······
2001*(1/8-1/2009)+8*(1/2001-1/2009)-2009*(1/8+1/2001)+8
计算2001*(1/8-1/2009) 8*(1/2001-1/2009) 2009*(1/8-1/2001)
2001*(1/8-1/2009)+8*(1/2001-1/2009)-2009*(1/8+1/2001)+8等于多少?
2001*(1/8-1/2009)+8*(1/2001-1/2009)-2009*(1/8+1/2001)+8等于多少?
2001*(1/8-1/2009)+8*(1/2001-1/2009)-2009*9(1/8+1/2001)+8 简算
2001*(1/8-1/2009)+8*(1/2001-1/2009)-2009*(1/8+1/2001)+82001*(1/8-1/2009)+8*(1/2001-1/2009)-2009*(1/8+1/2001)+8
9÷8+1÷8+3÷4
2001×(1/8-1/2009)+8×(1/2000-1/2009)-2009×(1/8+1/2001)
1+1÷2+1÷4+1÷8+1÷16+1÷32+1÷64
1÷(1÷2)÷(2÷3)÷(3÷4)÷.÷(8÷9)÷(9÷10)=?
(-8)÷[(-3/8)-(-11/8)]-1
[9又2009分之2008-(8-2009分之1)]÷2×2分之1
2000÷(2000÷2001分之2000)= 9分之1×81.36= 0.125×8分之1= (166+20分之1)÷41
1÷7/8=?
用简便方法 2001×(8分之1-2009分之1)+8×(2001分之1-2009分之1)-2009×(8分之1+2001分之1)+8
求2001*(1/8-1/2009)+8*(1/2001-1/2009)-2009*(1/8+1/2001)+8的简便方法是什么,要详细一点的.重谢.
简便算法题2001*(1/8 - 1/2009)+8*(1/2001 - 1/2009)-2009*(1/8 + 1/2001)+81/8等等都是分数.不是除法