(sina5π/12+cos5π/12)(sin5π/12-cos5π/12)

来源：学生作业帮助网编辑：作业帮时间：2024/04/30 09:54:59

(sina5π/12+cos5π/12)(sin5π/12-cos5π/12)
(sina5π/12+cos5π/12)(sin5π/12-cos5π/12)

(sina5π/12+cos5π/12)(sin5π/12-cos5π/12)
（sin5π/12+cos5π/12)(sin5π/12-cos5π/12)=sin²5π/12-cos²5π/12
=(1-cos5π/6)/2-(1+cos5π/6)/2
=(1+√3/2)/2-(1-√ 3/2)/2
=√3/2

(sin5π/12+cos5π/12)(sin5π/12-cos5π/12)
(sin5π/12+sinπ/12)(sin5π/12-sinπ/12)
=2sinπ/4cosπ/6 /2sinπ/6cosπ/4
=cotπ/6
=√3

[sin(5π/12)]^2 -[cos(5π/12)]^2=-cos(10π/12)=cos(π/6)=√3/2

(sina5π/12+cos5π/12)(sin5π/12-cos5π/12) sinπ/12cos5π/12等于求cos5π/12sinπ/12 cos5分之π×cos5分之2π 为什么cos5π/12等于sinπ/12 cos5π/12=sinπ/12 怎么算的? cosπ/12*cos5π/12结果是1/4 cos5π/12-根3sin5π/12过程把下列三角函数值从小到大排列起来：sin4/5π,-cos5/4π,sin32/5π,cos5/12π. 计算cos5分之π+cos5分之2π+cos5分之3π+cos5分之4π cos5π等于= 计算cos5分之π+cos5分之2π+cos5分之3π+cos5分之4π cos5π的三角函数值, (sin5π/12+cos5π/12)(sinπ/12-cosπ/12) (sin5π/12-sinπ/12)(cos5π/12+cosπ/12)=? cos5/12πcosπ/12+cosπ/12sinπ/6=? cos5π/12-tanπ/3sin5π/12的值是 sin5/12π×cos5/12π怎么算?请给出详细过程谢谢高手了..