作业帮计算：x(x-1)(x+1)(x+2)-24
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/04 14:21:44
计算：x(x-1)(x+1)(x+2)-24
计算：x(x-1)(x+1)(x+2)-24
计算：x(x-1)(x+1)(x+2)-24
x(x - 1)(x + 1)(x + 2) - 24
= x(x^2 - 1)(x + 2) - 24
= x(x^3 + 2x^2 - x - 2) - 24
= x^4 + 2x^3 - x^2 - 2x - 24
= (x^4 - 2x^3) + 4x^3 - x^2 - 2x - 24
= x^3(x - 2) + 4x^3 - 8x^2 + 7x^2 - 2x - 24
= (x^3 + 4x^2)(x - 2) + (7x^2 - 14x) + (12x - 24)
= (x^3 + 4x^2 + 7x + 12)(x - 2)
= [(x^3 + 3x^2) + (x^2 + 3x) + (4x + 12)](x - 2)
= (x^2 + x + 4)(x + 3)(x - 2)
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计算：x(x-1)(x+1)(x+2)-24
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