f(x)=x(x-1)(x-2)(x-3)(x-4) f'(1)=?求详解

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f(x)=x(x-1)(x-2)(x-3)(x-4) f'(1)=?求详解

f(x)=x(x-1)(x-2)(x-3)(x-4) f'(1)=?求详解
f(x)=x(x-1)(x-2)(x-3)(x-4) f'(1)=?
求详解

f(x)=x(x-1)(x-2)(x-3)(x-4) f'(1)=?求详解
f'(1)=lim(x->1)[f(x)-f(1)]/(x-1)
=lim(x->1)[x(x-1)(x-2)(x-3)(x-4)]/(x-1)
=lim(x->1)[x(x-2)(x-3)(x-4)]
=1×（-1）×（-2）×（-3）
=-6

f'(1)=lim(x->1)[f(x)-f(1)]/(x-1)
=lim(x->1)[x(x-1)(x-2)(x-3)(x-4)]/(x-1)
=lim(x->1)[x(x-2)(x-3)(x-4)]
=1×（-1）×（-2）×（-3）
=-6

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