若(x²-3xy+y+x-5)+3x+1的绝对值=0,则x²-3xy+y-2=多少

若(x²-3xy+y+x-5)+3x+1的绝对值=0,则x²-3xy+y-2=多少
若(x²-3xy+y+x-5)+3x+1的绝对值=0,则x²-3xy+y-2=多少

若(x²-3xy+y+x-5)+3x+1的绝对值=0,则x²-3xy+y-2=多少
|(x2-3xy+y+x-5)+3x+1|=0
|(x2-3xy+y)+x-5+3x+1|=0
|(x2-3xy+y)+(4x-4)|=0
x2-3xy+y=|4x-4|