作业帮化简[tan(-a-π)*sin(2π+a)]/[cos(-a)*tana]
来源：学生作业帮助网 编辑：作业帮 时间：2024/04/30 18:05:22
![化简[tan(-a-π)*sin(2π+a)]/[cos(-a)*tana]](/uploads/image/z/3150317-29-7.jpg?t=%E5%8C%96%E7%AE%80%5Btan%28-a-%CF%80%29%2Asin%282%CF%80%2Ba%29%5D%2F%5Bcos%28-a%29%2Atana%5D)
化简[tan(-a-π)*sin(2π+a)]/[cos(-a)*tana]
化简[tan(-a-π)*sin(2π+a)]/[cos(-a)*tana]
化简[tan(-a-π)*sin(2π+a)]/[cos(-a)*tana]
[tan(-a-π)*sin(2π+a)]/[cos(-a)*tana]
= -tan(π+a). sina/ {cosa(sina/cosa)}
= - tana ( sina)/(sina)
= - tana