当m为何值时,方程2/x-(x-m)/(x²-x)=1+1/(x-1)无实数解.

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当m为何值时,方程2/x-(x-m)/(x²-x)=1+1/(x-1)无实数解.

当m为何值时,方程2/x-(x-m)/(x²-x)=1+1/(x-1)无实数解.
当m为何值时,方程2/x-(x-m)/(x²-x)=1+1/(x-1)无实数解.

当m为何值时,方程2/x-(x-m)/(x²-x)=1+1/(x-1)无实数解.
将方程2/x-(x-m)/(x²-x)=1+1/(x-1)两边同时乘以x²-x,得:
2(x-1)-(x-m)=x²-x+x,化简后有x²-x-(m-2)=0,
则由求根公式x=[-b±√(b^2-4ac)]/(2a),若无实数解,则根号下小于0,即:
1+4(m-2)

方程两边同乘x(x-1)即x^2-x
再化简 求Δ<0
结果m>-7/4