x是钝角,sinx=1/3,求cos2x-sin2x/cosx^2

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/29 12:14:06
x是钝角,sinx=1/3,求cos2x-sin2x/cosx^2

x是钝角,sinx=1/3,求cos2x-sin2x/cosx^2
x是钝角,sinx=1/3,求cos2x-sin2x/cosx^2

x是钝角,sinx=1/3,求cos2x-sin2x/cosx^2
x是钝角,sinx=1/3,cosx=-2√2/3
(cos2x-sin2x)/cosx^2
=(cos^2x-sin^2x-2sinxcosx)/cos^2x
=(8/9-1/9+2*1/3*2√2/3)/(8/9)
=(8-1+4√2)/8
=(5+4√2)/8