If the equation m(x-1)=2001-n(x-2) for x has infinite roots ,then m的2001次方+n的2001次方=（英汉小词典：equation方程,infinite roots 无数个根）

If the equation m(x-1)=2001-n(x-2) for x has infinite roots ,then m的2001次方+n的2001次方=（英汉小词典：equation方程,infinite roots 无数个根）
If the equation m(x-1)=2001-n(x-2) for x has infinite roots ,then m的2001次方+n的2001次方=
（英汉小词典：equation方程,infinite roots 无数个根）

If the equation m(x-1)=2001-n(x-2) for x has infinite roots ,then m的2001次方+n的2001次方=（英汉小词典：equation方程,infinite roots 无数个根）
If the equation（方程） m(x-1)=2001-n(x-2) for x has infinite roots（无限个根） , then m的2001次方+n的2001次方= 0
因为X有无限个根,所以先令X＝1,得出0＝2001－n(-1),再令X＝2,得出m=2001
所以m=2001,n=-2001.
所以m的2001次方+n的2001次方=0