已知︱x+y-2︱+(2xy-1)2=0,求x2+6xy=y2的值

已知︱x+y-2︱+(2xy-1)2=0,求x2+6xy=y2的值
已知︱x+y-2︱+(2xy-1)2=0,求x2+6xy=y2的值

已知︱x+y-2︱+(2xy-1)2=0,求x2+6xy=y2的值
︱x+y-2︱+(2xy-1)2=0 x+y-2=0,x+y=2 2xy-1=0,xy=1/2 x2+6xy+y2=x2+2xy+y2+4xy=(x+y)^2+4xy=2^2+4*(1/2)=6 ^2是平方的意思