解方程:(1)1/(x+1)=2/(x-1) (2)1/(x+2)+3=x-1/x-2

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解方程:(1)1/(x+1)=2/(x-1) (2)1/(x+2)+3=x-1/x-2

解方程:(1)1/(x+1)=2/(x-1) (2)1/(x+2)+3=x-1/x-2
解方程:(1)1/(x+1)=2/(x-1) (2)1/(x+2)+3=x-1/x-2

解方程:(1)1/(x+1)=2/(x-1) (2)1/(x+2)+3=x-1/x-2
解①由1/(x+1)=2/(x-1)
得2(x+1)=x-1
即2x+2=x-1
解得x=-3
检验x=-3是方程的根
②由1/(x+2)+3=x-1/(x-2)
两边乘以(x+2)(x-2)
即(x-2)+3(x+2)(x-2)=(x-1)(x+2)
即x-2+3(x^2-4)=x^2+x-2
即x-2+3x^2-12=x^2+x-2
即2x^2=12
即x^2=6
即解得x=±√6
检验x=±√6是方程的根